token接口是按照springcloud oauth2的标准结构返回的。
成功
{ "tenant_id": "000000", "user_id": "1123598821738675201", "dept_id": "1123598813738675202,1123598813738675203", "post_id": "1123598817738675201", "role_id": "1123598816738675201", "oauth_id": "", "account": "admin", "user_name": "admin", "nick_name": "管理员", "real_name": "管理员", "role_name": "administrator", "avatar": "https://gw.alipayobjects.com/zos/rmsportal/BiazfanxmamNRoxxVxka.png", "access_token": "eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzUxMiJ9.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.P-oQ9F3B25pXjZuWCFk0CUfX4YgWOwGvZn4YgQq14qfAAetFCfAzVkwpT7cosTEF4CKDstca1V9cP8JwDJ7M_w", "refresh_token": "eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzUxMiJ9.eyJpc3MiOiJibGFkZXguY24iLCJhdWQiOlsiYmxhZGV4Il0sInRva2VuX3R5cGUiOiJyZWZyZXNoX3Rva2VuIiwidXNlcl9pZCI6IjExMjM1OTg4MjE3Mzg2NzUyMDEiLCJkZXB0X2lkIjoiMTEyMzU5ODgxMzczODY3NTIwMiwxMTIzNTk4ODEzNzM4Njc1MjAzIiwicm9sZV9pZCI6IjExMjM1OTg4MTY3Mzg2NzUyMDEiLCJleHAiOjE3MzEwMzY0OTYsIm5iZiI6MTczMDQzMTY5Nn0.7nQl8sOal8FcFr-vJTcqG8R-kTeSeB9dPrN81fqamVZyQ-PIMJRTr5d0dG2qpTYJt4d3n-L-P8Aj5x-UBd6YHg", "token_type": "bearer", "expires_in": 3600, "detail": { "type": "web" }, "license": "powered by bladex" }
错误
{
"success": false,
"error_code": 2004,
"error_description": "验证码不正确"
}
除此以外其他的接口是这样的返回
{
"code": 200,
"success": true,
"data": {
},
"msg": "操作成功"
}
讨论(0)
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也就这样标准了对吧? 然后我让app去做处理就好了对吗?
作者追问:2024-11-01 14:33
是的,主要就是token的标准是oauth2格式,变化会多一些。其他的接口就都是统一的了。
讨论(0)
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